doumen5895 2017-04-07 16:27
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PHP零整数被评估为false

As the title says, PHP seems to be evaluating the integer value 0 as false.

Take for example this snippet:

http://sandbox.onlinephpfunctions.com/code/13d885fb68359a3154999c2ef85db7c913c49bc5

<?php

if($exists = checkDup()){
    echo $exits;
}
else{
    echo "error!";  
}

function checkDup ($foo = 'blah', $bar = 'blah'){
    if ($foo == $bar) return (int) 0;
    return false;
}

As you can see, despite casting the reply as an int PHP parsing the return as false which in incorrect.

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2条回答 默认 最新

  • dongtang5776 2017-04-07 16:35
    关注

    PHP is evaluating a lot to false ;) For example null, '', 0 You have to include a type check as well, you can do so by using === or !==

    $exists = checkDup();
    if($exists !== false){
        echo $exits;
    }
    else{
        echo "error!";  
    }
    
    function checkDup ($foo = 'blah', $bar = 'blah'){
        if ($foo == $bar) return 0;
        return false;
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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