有关C语言数组的疑问，求解惑

Question

运行结果是12345，我自己演算只能出来12344，不晓得错哪了，有谁能列举一下每次循环后数组变成什么，让我看看我哪里出问题了

Answer 1

• i = 0, n = 0, i < 10, c = a[0] = 1
  • j = 1, j < 10, a[j]=a[1]=2, 2==1 不成立
  • j = 2, j < 10, a[j]=a[2]=2, 2==1 不成立
  • ...
  • j = 8，j < 10, a[j]=a[8]=1, 1==1, 成立
    • k = 8, k < 10, a[8] = a[9] = 5; n++; n = 1;
      a = {1, 2, 2, 3, 4, 3, 4, 5, 5, 5}
• i = 1, n = 1, i < 9, c = a[1] = 2
  • j = 2, j < 9, a[j]=a[2]=2, 2==2 成立
    • k = 2，k < 9; 后一位覆盖前一位; n++; n = 2;
      a = {1, 2, 3, 4, 3, 4, 5, 5, 5, 5}

• i = 2, n = 2, i < 8, c = a[2] = 3

  • j = 3, j < 8, a[j]=a[3]=4, 4==3 不成立
  • j = 4, j < 8, a[j]=a[4]=3, 3==3 成立
    • k = 4，k < 8; 后一位覆盖前一位；n++; n = 3;
      a = {1, 2, 3, 4, 4, 5, 5, 5, 5, 5}

• i = 3, n = 3, i < 7, c = a[3] = 4

  • j = 4, j < 7, a[j]=a[4]=4, 4==4 成立
    • k = 4, k < 7; 后一位覆盖前一位；n++; n = 4;
      a = {1, 2, 3, 4, 5, 5, 5, 5, 5, 5}

• i = 4, n = 4, i < 6, c = a[4] = 5

  • j = 5, j < 6, a[j]=a[5]=5, 5==5 成立
    • k = 5, k < 6; 后一位覆盖前一位 n++; n = 5;
      a = {1, 2, 3, 4, 5, 5, 5, 5, 5, 5}

• i = 5, n = 5; i < 5; 不成立，退出循环

• 遍历从 i = 0， i<5; 输出 1 2 3 4 5