dpjtn48868 2016-12-26 10:08
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计数包含特定字符串的数组键

I have an array like that contain key with same name but with number at the end

array example:

Array
(
    [field_name0] => name 
    [field_name1] => sku_package_height 
    [field_name2] => sku_package_width
    [custom_field] => 13
    [attribute] => 'test'
    [field_name3] => sku_package_length 
    [field_name4] => sku_package_weight
)

from the example above i want to count how many record that has array key that contain field_name, so the result I want will be 5

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4条回答 默认 最新

  • dqqpf32897 2016-12-26 10:11
    关注

    You can do it like below:-

    <?php
    $original_array = Array
    (
        'field_name0' => 'name',
        'field_name1' => 'sku_package_height',
        'field_name2' => 'sku_package_width',
        'custom_field' => 13,
        'attribute' => 'test',
        'field_name3' => 'sku_package_length',
        'field_name4' => 'sku_package_weight'
    );
    $search = "field_name";
    $counter = 0;
    foreach($original_array as $key=> $value){
        if(strstr($key,$search)){
           $counter = $counter+1;
        }
    }
    
    echo $counter;
    

    Output:-https://eval.in/704506

    Or

    <?php
    $original_array = Array
    (
        'field_name0' => 'name',
        'field_name1' => 'sku_package_height',
        'field_name2' => 'sku_package_width',
        'custom_field' => 13,
        'attribute' => 'test',
        'field_name3' => 'sku_package_length',
        'field_name4' => 'sku_package_weight',
    );
    $search = "field_name";
    $counter = 0;
    foreach($original_array as $key=> $value){
        if(is_numeric(strpos($key,$search))){
           $counter = $counter+1;
        }
    }
    
    echo $counter;
    

    Output:-https://eval.in/704518

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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