如何在括号正则表达式中获取括号外的字符串

Question

I need help trying to get regex to work with double brackets

currently i have this for the regex

(\\[.*?\\])

that allows me to get everything inside a bracket,

HOWEVER my string has double brackets

[DATA1[OTHERDATA]RUBBISH]

the output I get is

[DATA1[OTHERDATA]

is the a way of getting the full bracket including the bracket inside?

Answer 1

Keeping things nice and simple. A greedy match should do the trick:

/\[(.+)\]/

the .+ will match any character, but it'll stop at the last ], so the match will be "DATA1[OTHERDATA]RUBBISH"

Demo

Breakdown is really simple:

• \[: Matches literal [
• (.+): Match (and capture) all characters - including opening and closing brackets
• \]: Match literal ]

Regardless of how many nested brackets you have the results are the same:

[data[foo][bar][eve[n]]more]
//match:
data[foo][bar][eve[n]]more