如何只显示print_r的第一行？

Question

How do you echo only the first line of print print_r?

More info:

I have this PHP code:

preg_match_all('/MbrDtlMain.php\?([^ ]+)>/i', $string, $matches);
foreach(end($matches) as $key=> $value){
    print print_r($value, 1).'<br>';
}

That results in:

12567682
12764252
12493678
14739908

(or other numbers depending on user input)

I tried:

preg_match_all('/MbrDtlMain.php\?([^ ]+)>/i', $string, $matches);
foreach(end($matches) as $key=> $value){
    $id = print_r($value, 1).'<br>';
}
echo $id

But it results in 1 random number from the list. In other words, the result only shows when using print like ' print print_r($value, 1).'<br>';'. The problem is that I only want the first, inorder, result to be shown. As if:

$firstlineofnumbers = '12567682';
echo $firstlineofnumbers;

Hope this makes sense. Thanks (:

Answer 1

If I understood what you're trying to do, just adding a break; statement after outputting the first value should be enough:

foreach(end($matches) as $key=> $value){
    print print_r($value, true).'<br>'; // print_r() expects true, not 1
    break;
}