与n个数字字符匹配的正则表达式，以及1或2个非数字字符

Question

I've been using a standard ([0-9]+) pattern to match numbers in a string, but have a strange edge case now. I want to match the following:

123
456
.123
123.
%123
31st
14th
2nd
100.55
555.10

In the above cases, the non-numeric characters are:
.
%
s
h
n
d

But they could be a variety of characters.
Thoughts?

JS or PHP would be great.

Answer 1

I tried to create several rules for all cases :

(\d+(?:\.\d*)?)        // 123 ; 123. ; 123.45
([%.]\d+)              // %123 ; .123
(\d+(?:st|nd|th))      // 31st ; 2nd ; 14th

Then mixed :

((?:\d+(?:\.\d*)?)|(?:[%.]\d+)|(?:\d+(?:st|nd|th)))

If you want something shorter, you can simply use ([%.\dshnd]+), but this will catch many non-wanted entries, like %%123%%.