I try to do this echo date("Y", strtotime("1999-00-00"));
but instead of 1999
it returns 1998
. Is there a way how to handle this? I would prefer a "clean way", not something like $finalYear = (float)$year+1
etc.
The date format MUST be YYYY-00-00
(with zeros)
date()仅从日期格式YYYY-00-00开始
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4条回答 默认 最新
- dqx76962 2012-02-23 18:49关注
If you're absolutely sure that the date's format will never change, you'd be better off with
echo substr('1999-00-00', 0, 4);
rather than incurring the heavy overhead of strtotime() and roundtripping through the entire date/time subsystem.
When you tell PHP's date functions that the month/day are 0, which are "invalid", it'll convert those to the appropriate "previous" values.
e.g.
1999-00-10 is actually 1998-12-10 1999-11-00 is actually 1999-10-31
and so on. It's like saying "yesterday" or "last month". similarly, specifying month 13 makes it
1999-13-01 is actually 2000-01-01
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