C语言循环单链表输出错误

Question

输出结果：

#include<stdio.h>
#include<stdlib.h>
#include<malloc.h>
//函数声明
void printNode(struct Node *head);
void createNode(struct Node *head);
//创建链表
struct Node{
    int data;
    struct Node *next;
}Node;
//链表初始化
struct Node *intList() {
    struct Node *head = (struct Node *)malloc(sizeof(struct Node));
    head->data = 0;
    head->next = head;
    return head;
}
//创建结点
void createNode(struct Node *head, int i) {
    struct Node *tail = (struct Node *)malloc(sizeof(struct Node));
        tail->data = i;
        tail->next = head->next;
        head->next = tail;        
        printf("%d ", i);
}
//打印数据
void printNode(struct Node *head) {
    struct Node *node = head->next;
    printf("输出数据：");
    for(int i = 0; i < 10; i++) {
        if (node = head) {
            node = node->next;
        }
        printf("%d ", node->data);
        node = node->next;
    }
}
//主函数
int main() {
    struct Node *list = intList();
    for (int i = 0; i < 5; i++) {
        createNode(list, i);
    }
    printNode(list);
    return 0;
}

Answer 1

printNode 那里是 node == head 不是 node = head