PHP：使用-1-和-10-等值对数组进行排序

Question

I have a function that gets filenames from a directory, and then puts them in an array. All the filenames start with a code, as an example: -0-filename.php, -1-filename.php, -2-filename.php and -10-filename.php.

After some steps, the filenames are echoed out. The process looks like this:

rsort( $archiveArray );
$amount = count( $archiveArray );
$i = 0;
while( $i <= $amount )
{
    echo $archiveArray[$i];
    $i++;
}

Anyways. The problem is; when I get 10 files in the directory, and try to do the echoing process above, I get the names in a wrong order. - It's supposed to be :

-10-filename.php

-9-filename.php

-8-filename.php

...

-1-filename.php

-0-filename.php

But instead, I get

-9-filename.php

-8-filename.php

...

-10-filename.php

-1-filename.php

-0-filename.php

What's the quickest and easiest way to fix this?

EDIT:

If it wasn't obvious, the filenames are not always identical, even when not including the codes. The are always in this format: -number-randomtext.php, where number is always one higher than the last one, and randomtext can really be anything.

Answer 1

Using rsort with SORT_NATURAL works if you're running PHP 5.4. If you're not, however:

natsort( $archiveArray );
$archiveArray = array_reverse( $archiveArray );

...will do the same thing. Just use natsort to do the natural order sorting, then reverse the array.

Test code (PHP 5.3.3):

php > $array = array( '-1-blah', '-2-foo', '-12-boo', '-11-yaay', '-3-bar' );
php > natsort( $array );
php > print_r( $array );
Array
(
    [0] => -1-blah
    [1] => -2-foo
    [4] => -3-bar
    [3] => -11-yaay
    [2] => -12-boo
)
php > $array = array_reverse( $array );
php > print_r( $array );
Array
(
    [0] => -12-boo
    [1] => -11-yaay
    [2] => -3-bar
    [3] => -2-foo
    [4] => -1-blah
)
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