根据打开的页面的itemid值,查询name,然后将itemid对应的name的值打印出来,需要根据当前代码做修改,感谢~
```python
import random
import string
import pymysql
import cherrypy
import os
import json
import os
import sys
import scene_reader
from tools import check_labels as check
import urllib.parse
url = '*********/?itemid=1'
parsed_url = urllib.parse.urlparse(url)
params = urllib.parse.parse_qs(parsed_url.query)
itemid = params['itemid'][0]
try:
conn = pymysql.connect(host="localhost", user="*", password="*", database="*")
except pymysql.Error as e:
print ("error")
cursor = conn.cursor()
cursor.execute("select name from test where id='1'")
datas = cursor.fetchall()
datass = datas[0][0]
print (datass)
```