转换数组中替换的字符串

Question

I have the following code:

<?php
$text = 'Hey @Mathew, have u talked with @Jhon today?';
    $text = preg_replace('/(^|\s)@([A-Za-z0-9]*)/', '\1<a href="profile.php?user=\\2">@\\2</a>',$text);
?>

And my goal is notify the user was quoted. To do that, I thought: I put all the replaced strings in a array and pick only the name; using the example above, and following the thinking, I have this result:

['Mathew', 'Jhon']

So, how can I have the last result?

Answer 1

You may actually collect matches while performing a regex-based search and replace if you use preg_replace_callback:

$text = 'Hey @Mathew, have u talked with @Jhon today?';
$names = [];
$text = preg_replace_callback('/(^|\s)@([A-Za-z0-9]*)/', function($m) use (&$names) {
        $names[] = $m[2];
        return $m[1] . '<a href="profile.php?user=' . $m[2] . '">@' . $m[2] . '</a>';
    },$text);
echo "$text
";
print_r($names);

See the PHP demo

Output:

Hey <a href="profile.php?user=Mathew">@Mathew</a>, have u talked with <a href="profile.php?user=Jhon">@Jhon</a> today?
Array
(
    [0] => Mathew
    [1] => Jhon
)

Note the array variable for the matches is passed to the anonymous function with the use (&$names) syntax. The $m is a match object containing the whole match in the first item and captures in the subsequent items.