如果存在PHP加载图像？

Question

I am using this code for a slideshow:

<img src="<?php echo($array[0]); ?>"/>
<img src="<?php echo($array[1]); ?>"/>
<img src="<?php echo($array[2]); ?>"/>
<img src="<?php echo($array[3]); ?>"/>
<img src="<?php echo($array[4]); ?>"/>
<img src="<?php echo($array[5]); ?>"/>
<img src="<?php echo($array[6]); ?>"/>
<img src="<?php echo($array[7]); ?>"/>

I want to show images, only if they exist. Sometimes the $array has only 5 values.

How is this posible?

Answer 1

You should loop over the array values and echo an image tag for each value:

<?php
foreach($array as $img){
    echo '<img src="'.$img.'"/>'."
";
}
?>