用正则表达式替换字符串

Question

I'm trying to extract from a string like this:

$message = #porrabarça per avui @RTorq el  @FCBar guanyarà per 3-1 al AC Milan

The '3-1'. As Number - Number

I've tried

$message = preg_replace('/[0-9]\s*-\s[0-9]/i', '', $message);

But it isnt working. It's output is the same as the input.

Can you help me out?

Answer 1

The problem is \s here.

/[0-9]\s*-\s[0-9]/
           ^
           |
           +--- This makes a single space mandatory. 

You need \s* there. Use preg_match to extract anything. preg_match matches and optionally set the match to a variable. From there you can extract the matches. preg_replace replaces the matched content.

preg_match("/\d+\s*-\s*\d+/", $message, $match);
$num = $match[0];

http://ideone.com/BWKZQV

To replace use this pattern and empty string as replace string in preg_replace.

A better pattern would using POSIX character classes. it'll match any type digit characters of any other locale.

/[[:digit:]]+[[:space:]]*-[[:space:]]*[[:digit:]]+/