这jieba 分词代码在python上运行，有什么错误的地方吗？

Question

# 机器人给我的代码，在安卓手机上termux使用

import jieba

def analyze_text(text):
    # 分词并拼接为字符串
    words = jieba.lcut(text)
    seg_result = ' '.join(words)

    # 统计词语出现次数
    word_count = {}
    for word in words:
        if word in word_count:
            word_count[word] += 1
        else:
            word_count[word] = 1

    # 统计负面词语
    negative_words = []
    for word in words:
        if word in ["不好", "糟糕", "差"]:
            negative_words.append(word)

    # 词语归纳
    categories = {}
    for word in words:
        category = ''

        if word == '苹果':
            category = '水果'
        elif word == '电视':
            category = '电子产品'

        # 根据其他需求进行更多归纳判断
        # ...

        if category:
            if category in categories:
                categories[category].append(word)
            else:
                categories[category] = [word]

    return {
        "segmented_text": seg_result,
        "word_count": word_count,
        "negative_words": negative_words,
        "categories": categories
    }

# 输入一句话
input_text = input("请输入一句话：")

# 调用函数进行分析
analysis_result = analyze_text(input_text)

# 打印结果
print("分词结果：", analysis_result["segmented_text"])
print("词语统计：", analysis_result["word_count"])
print("负面词语：", analysis_result["negative_words"])
print("词语归纳：", analysis_result["categories"])

>>> print("分词结果：", analysis_result["segmented_text"])
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'NoneType' object is not subscriptable
>>> print("词语统计：", analysis_result["word_count"])
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'NoneType' object is not subscriptable
>>> print("负面词语：", analysis_result["negative_words"])
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'NoneType' object is not subscriptable
>>> print("词语归纳：", analysis_result["categories"])
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'NoneType' object is not subscriptable

Answer 1