dongqiangse6623 2016-05-03 22:00
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如何在php中定位嵌套的JSON对象,并回显它们?

Okay, so I think you get what I wanna do by just watching the code.

//Get JSON text file (Steam API)
$json = file_get_contents('http://store.steampowered.com/api/appdetails?appids=57690');

//Decode JSON
$game_json = json_decode($json, true);

//Target game name and echo it
echo $game_json['name'];

The JSON itself comes in this order (unstructured, very sorry):

{"57690":{"success":true,"data":{"type":"game","name":"Tropico 4: Steam Special Edition"

So my target is ""name":"Tropico 4: Steam Special Edition"", which is what I want to echo on my page. I'm not sure if it helps, but "name": appears once, is something like [0] needed in my code to target the first? Is the nesting what's stopping me here, or is the $game_json['name']; an incorrect way of targeting?

ANY tips and/or help will be much appreciated. Thanks.

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2条回答 默认 最新

  • dragon188199 2016-05-03 22:05
    关注

    In the future, use print_r($game_json) to check the array structure.

    <?php
    $json = file_get_contents('http://store.steampowered.com/api/appdetails?appids=57690');
    $game_json = json_decode($json, true);
    echo $game_json['57690']['data']['name'];
    //Tropico 4: Steam Special Edition
    echo $game_json['57690']['data']['required_age'];
    //0
    //etc...
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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