$ _POST [$ variable]不起作用[关闭]

Question

For input form I need random input name and id

I created random values $token_hash = random

Then input field

 <input type="hidden" name="' .$token_hash .'" id="' .$token_hash .'" value="some_value">

Next above input form is php code to check what values get from form

 echo $_POST[$token_hash] .' $_POST[$token_hash]<br>';

Problem is that $_POST[$token_hash] echo blank value (no value)....

I tried also $_POST[' .$token_hash .'] but do not work.

Other $_POST works, but they are like $_POST['some_value']

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Seems finally get solution. Do not understand why it did not work before. If useful for someone else. Here is solution.

Create random value $token_hash = sha1(uniqid($time_when_form_submitted .'token' .$_SERVER["REMOTE_ADDR"]));

Then create session $_SESSION['token_hash'] = $token_hash;

Then pass session to input

echo '<input type="hidden" name="' .$_SESSION['token_hash'] .'" id="' .$_SESSION['token_hash'] .'" value="' .$_SESSION['token'] .'">'

Then get session value from input. This code must be above all previos $token_hash_from_input = $_SESSION['token_hash'];

Then with $_POST[$token_hash_from_input]) get input value

Answer 1

you need to do it like this,

$_POST["token_hash"]

if that token_hash has really been posted, you will get one