doucheng9304 2012-10-11 19:00
浏览 18
已采纳

Php的准备声明

I was following the prepared statement example on the php.net site and I cant seem to get my version to work.

$link = mysql_connect("localhost","root","mypassword") or die (mysql_error());

$query= $link->prepare("select * from users WHERE userid = ? AND password=password('?')");
$query->bindParam(1, $userid);
$query->bindParam(2, $password);
$query->execute();

if (mysql_num_rows($query)==1)
    {
        echo "Welcome, ",$userid,"
";
    }
    mysql_close($link);

I get the error: syntax error, unexpected T_VARIABLE

  • 写回答

3条回答 默认 最新

  • drflkphi675447 2012-10-11 19:02
    关注

    Change echo "Welcome, ",$userid," ";

    to

    echo "Welcome, " . $userid . " ";

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 微信小程序协议怎么写
  • ¥15 c语言怎么用printf(“\b \b”)与getch()实现黑框里写入与删除?
  • ¥20 怎么用dlib库的算法识别小麦病虫害
  • ¥15 华为ensp模拟器中S5700交换机在配置过程中老是反复重启
  • ¥15 java写代码遇到问题,求帮助
  • ¥15 uniapp uview http 如何实现统一的请求异常信息提示?
  • ¥15 有了解d3和topogram.js库的吗?有偿请教
  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看