c语言pat基础题0901L1075

Question

#include<stdio.h>
int main(){
    int number,front,rear,flag;
    scanf("%d",&number);
    if(number/10000>0){
        front=number/100;
        rear=number%100;
        if(rear<=9){
            printf("%d-0%d",front,rear);
        }else{
            printf("%d-%d",front,rear);
        }
    }else{
        front=number/100;
        rear=number%100;
        if(front<22){
            flag=20;
        }else{
            flag=19;
        }
        if(rear<=9&&front<=9){
            printf("%d0%d-0%d",flag,front,rear);
        }else if(rear>9&&front<=9){
            printf("%d%d-%d",flag,front,rear);
        }else if(rear<=9&&front>9){
            printf("%d%d-0%d",flag,front,rear);
        }else{
            printf("%d%d-%d",flag,front,rear);
        }
    }
}

我的代码出现问题，本题希望可以得到大家的指导，谢谢你的帮助！

Answer 1

修改如下，供参考：

#include <stdio.h>
int main() 
{
    int n = 0, a, b;
    scanf("%d", &n);
    if (n / 1000 < 10) {
        a = n / 100;
        b = n % 100;
        if (a < 22) 
            printf("20%02d-%02d", a, b);
        else 
            printf("19%02d-%02d", a, b);
    }
    else {
        a = n / 100;
        b = n % 100;
        printf("%02d-%02d", a, b);
    }
    return 0;
}