doushu2699 2012-01-25 12:01
浏览 121
已采纳

如何编写一个替换锚点和链接值的正则表达式

My html code has many anchors and links such as :

<script src="/Common/Scripts/jquery-1.4.4.min.js" type="text/javascript"></script>  
<link href="/Common/Css/UserAdmin.css" rel="stylesheet" type="text/css" />
<a href="/test.php">test</a></li> 

I want to change them into:

<script src="http://www.mydomain.com/Common/Scripts/jquery-1.4.4.min.js" type="text/javascript"></script>  
<link href="http://www.mydomain.com/Common/Css/UserAdmin.css" rel="stylesheet" type="text/css" />
<a href="http://www.mydomain.com/test.php">test</a></li> 

ie. add a http://www.mydomain.com before every src and href value, how to achieve this using regex expression. PS: I use PHP language.

  • 写回答

2条回答 默认 最新

  • dongou3158 2012-01-25 12:30
    关注

    Use the following regexp:

    ([\b]*)(src|href)([\b]*=[\b]*")(.+?")
    

    and replace with:

    \1\2\3http://www.mydomain.com\4
    

    The main idea here is to use the lazy operator "+?"

    Group1: ([\b]*)          0 or more blanks ... followed by 
    Group2: (src|href)       src or href ... followed by 
    Group3: ([\b]*=[\b]*")   0 or more blanks followed by = followed by 0 or more blanks followed by a quote ... followed by 
    Group4: (.+?")           any group of characters until the nearest quote
    

    then replace with what has matched Group1 then Group2 then Group3, insert http://www.mydomain.com, then what has matched Group4

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 sqlite 附加(attach database)加密数据库时,返回26是什么原因呢?
  • ¥88 找成都本地经验丰富懂小程序开发的技术大咖
  • ¥15 如何处理复杂数据表格的除法运算
  • ¥15 如何用stc8h1k08的片子做485数据透传的功能?(关键词-串口)
  • ¥15 有兄弟姐妹会用word插图功能制作类似citespace的图片吗?
  • ¥200 uniapp长期运行卡死问题解决
  • ¥15 latex怎么处理论文引理引用参考文献
  • ¥15 请教:如何用postman调用本地虚拟机区块链接上的合约?
  • ¥15 为什么使用javacv转封装rtsp为rtmp时出现如下问题:[h264 @ 000000004faf7500]no frame?
  • ¥15 乘性高斯噪声在深度学习网络中的应用