以编程方式从drupal 8获取所有节点

Question

I am trying to get all nodes of a certian type from drupal. I have tried many ways to achieve that, but maybe due to my lack of Drupal custom module programming experience I couldn't achieve my desire. the closest way that I found on the web, is this:

    $nids = \Drupal::entityQuery('node')->condition('type','news')->execute();
    $nodes =  \Drupal
ode\Entity\Node::loadMultiple($nids); 

• the first line returns an object of id's
• the second line returns the nodes of those id's

this looks easy and straight forward. but, this is the output! { "59": { "in_preview": null }, "61": { "in_preview": null } }

can someone please help, what is wrong? and is this the correct way to do it ?

I want to take the nodes then search every one of them ( I am making some sort of search engine) so I expect some kind of an object that I can then extract the heading, body ... etc, from. is this the correct way ?

Answer 1

This actually returns node objects

$nodes =  \Drupal
ode\Entity\Node::loadMultiple($nids); 

perhaps your output gives minimal results and not objects. If you inspect with a proper debugger you will see the objects.

Perhaps its better to actually get one node object at a time if you expect too many nodes to be returned from the query

$query = \Drupal::entityQuery('node')
  ->condition('status', 1) //published or not
  ->condition('type', 'news') //content type
  ->pager(10); //specify results to return
$nids = $query->execute();

foreach ($nids as $nid) {
  $node = \Drupal
ode\Entity\Node::load($nid); 
  $body = $node->body->value;
  $title = $node->title->value;
  //...
}