duanfu1945 2013-05-13 03:51
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根据yii中的admin id提交的唯一

I am using Yii framework and i have 3 fields in my table named Table_Details and fields are table_number,seats and admin_id.I want to enter a unique table_number for each admin_id.If i use unique validation for field table_number,then it will insert table_number only once in the table but i want to insert table_number uniquely for each admin_id.

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  • douchen5971 2013-05-13 04:36
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    You can define your own rule. i.e.

    public function rules()
    {
        return array(
           array('table_number', 'uniqueTable', "on" => "insert"),
        );
    }
    

    And define a uniqueTable function in your model:

    public function uniqueTable($attribute,$params)
    {
        $record=TableDetail::model()->findByAttributes(array('table_name'=>$this->table_name, "admin_id" => Yii::app->user->id));
    
        if(count($record) > 0){
            $this->addError($attribute, 'You already have a table with this name');
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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