求大shen看一看怎么改，前端向后端传list

Question

找到解决办法，顺便记录一下，希望能帮到有类似问题的人
如图所示

Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is java.lang.IllegalStateException: No primary or single public constructor found for interface java.util.List - and no default constructor found either] with root cause

java.lang.IllegalStateException: No primary or single public constructor found for interface java.util.List - and no default constructor found either

本来是java.lang.IllegalArgumentException: Invalid character found in the request target [/deleteShoucang?a[0][post_url]=1&a[1][post_url]=2 ]. The valid characters are defined in RFC 7230 and RFC 3986 这个问题

解决起来很简单，不需要什么@什么的
首先是tomcat7.0以上传不了list，就是上面的问题，解决是创建一个类，内容是

import org.apache.catalina.connector.Connector;
import org.springframework.boot.web.embedded.tomcat.TomcatServletWebServerFactory;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
@Configuration
public class TomcatConfig {
    @Bean
    public TomcatServletWebServerFactory webServerFactory() {
        TomcatServletWebServerFactory factory = new TomcatServletWebServerFactory();
        factory.addConnectorCustomizers((Connector connector) -> {
            connector.setProperty("relaxedPathChars", "\"<>[\\]^`{|}");
            connector.setProperty("relaxedQueryChars", "\"<>[\\]^`{|}");
        });
        return factory;
    }
}

然后再创建一个vo类，就一个参数，LIst list，然后get，set那一揽子方法，这个类的名字是listList，那么接受参数的时候方法体是
public String test(listList list)

import java.util.List;

public class listList {
    List list;

    public listList() {
        super();
    }

    @Override
    public String toString() {
        return "listList{" +
                "list=" + list +
                '}';
    }

    public List getList() {
        return list;
    }

    public void setList(List list) {
        this.list = list;
    }

    public listList(List list) {
        this.list = list;
    }
}

@RestController
public class testController {
    @PostMapping("/test")
    public String  test(listList list){
        System.out.println(list);
        return "ok";
    }
}

Answer 1

前端写的没问题，java里面报错，这个得请专业java大神看看