C#怎么把json字符串解析出来

Question

{ "A":"one", "B":"two", "C":0, "D":[{ "time":"7:00", "signal":"a:1,b:2,c:3" },{ "tme":"8:00" , "signal":"a:4,b:5,c:6" }]}

如图，其中红线位置是重点，这样的怎么处理

Answer 1

先看运行结果：

示例代码：

using Newtonsoft.Json;

namespace ConsoleApp1;

static class Program
{
    static void Main()
    {
        var json = """
                   { "A":"one", "B":"two", "C":0, "D":[{ "time":"7:00", "signal":"a:1,b:2,c:3" },{ "tme":"8:00" , "signal":"a:4,b:5,c:6" }]}
                   """;

        var data = JsonConvert.DeserializeObject<Data>(json);

        foreach (var signalData in data.D)
        {
            Console.WriteLine("FinalTime: " + signalData.FinalTime);
            Console.WriteLine("Signal A: " + signalData.SignalObject.A);
            Console.WriteLine("Signal B: " + signalData.SignalObject.B);
            Console.WriteLine("Signal C: " + signalData.SignalObject.C);
        }
        Console.ReadKey();
    }
}

public class Data
{
    public string A { get; set; }
    public string B { get; set; }
    public int C { get; set; }
    public List<SignalData> D { get; set; }
}

public class SignalData
{
    public string Time { get; set; }
    public string Tme { get; set; }
    public string FinalTime => !string.IsNullOrEmpty(Time) ? Time : Tme;
    public string Signal { get; set; }

    public Signal SignalObject
    {
        get
        {
            var signal = new Signal();
            var splits = Signal.Split(new[] { "," }, StringSplitOptions.RemoveEmptyEntries);
            signal.A = int.Parse(splits[0].Split(':')[1]);
            signal.B = int.Parse(splits[1].Split(':')[1]);
            signal.C = int.Parse(splits[2].Split(':')[1]);
            return signal;
        }
    }
}

public class Signal
{
    public int A { get; set; }
    public int B { get; set; }
    public int C { get; set; }
}