从健盘上输入正整数n，利用递归方法求s=1/3+2/5+...+n/2n+1

Question

从健盘上输入正整数n，利用递归方法求s=1/3+2/5+...+n/2n+1

Answer 1

很常规的题目啊，看下这个，记得采纳哦

import java.util.Scanner;  
  
public class Main {  
    public static void main(String[] args) {  
        Scanner scanner = new Scanner(System.in);  
        System.out.println("请输入一个正整数：");  
        int n = scanner.nextInt();  
        System.out.println("结果是：" + recursiveSum(n));  
    }  
  
    public static double recursiveSum(int n) {  
        if (n == 1) {  
            return 1.0 / 3;  
        } else {  
            return (n / (2 * n + 1)) + recursiveSum(n - 1);  
        }  
    }  
}