layui如何动态绑定asp.net后台中的数据

Question

layui如何动态绑定asp.net后台中的数据
后台代码如下

 [WebMethod]
        public static string Get_work_order()
        {
            string sql = "select work_order  from   work_order where status = 1";
            DataTable tb = DBSql.GetDataTable(sql, "1");
            string json = Newtonsoft.Json.JsonConvert.SerializeObject(tb);
            return json;
        }

前台下拉框是这样的

```html
  <form class="layui-form">
 <div class="layui-form-item">
                    <label for="work_order" class="layui-form-label">工单编号</label>
                    <div class="layui-input-inline">
                        <select id="work_order" name="work_order" class="valid" lay-filter="work_orderFilter">
                             <option value="">工单编号</option>
                        </select>
                    </div>
  </form>

```

Answer 1

举个代码的例子如下：

／／ａｊａｘ函数调用服务器静态方法
callServerFunction("", "Get_work_order","", ss);

                function callServerFunction(serviceUrl,serverFuncName,params,resultFuncName,srcobj) {
                $.ajax({
                    //要用post方式   
                    type: "Post",
                    //方法所在页面和方法名   
                    url: (serviceUrl == "" ? (window.location.protocol + "//" + window.location.host + window.location.pathname) : serviceUrl) + "/" + serverFuncName,
                    contentType: "application/json; charset=utf-8",
                    data: params,
                    dataType: "json",
                    success: function (data) {
                        //返回的数据用data.d获取内容   
                        if (resultFuncName != null) {
                            resultFuncName("success", data.d,srcobj);
                        }
                    },
                    error: function (err) {
                        if (resultFuncName != null) {
                            resultFuncName("error", err);
                        }
                    }
                });
            }
//ajax 获取数据后将值赋予 id 为 ｔｅｓｔ　的 ｉｎｐｕｔ　ｓｅｌｅｃｔ
    function ss(type, result) {
           var json=eval(result);
           var des=document.getElementById("test");
           des.length=0;
           for (var i = 0; i < json.length; i++) {
                var option = new Option(json[i].orderno, json[i].orderno);
                des.add(option);
            }
    }