Php Regex关闭线上休息的开放标记

Question

I have html code like this :

<li>some text
more text

<li>some other text
any more text

I would like to close the list items. An Item shall be closed on a line break. The result shall look like this:

<li>some text<li>
more text

<li>some other text<li>
any more text

This is my regex, which does not work:

preg_replace("/<li>+(.*?)+/ig","\\2</li>", $o );

It returns nothing instead of:

<li>some text<li>
more text

<li>some other text<li>
any more text

Many Thanks

Answer 1

This regex will take all in the li-line and the \K will clear the match and set cursor to the right point:

<li>.*\K

Then replace with it:

</li>

Regex live here.

It is due the . don't match .

---

With effectiveness:

<li>.*(?:(?<!<\/li>)(?=\s*
))\K

Regex live here.