doukanmang3687
doukanmang3687
2011-08-27 12:14
浏览 68
已采纳

使用PHP implode + array返回逗号分隔列表?

I working on some WordPress code with the WP Alchemy class, and I'm trying to recall the meta values used in a page template as a comma separated list. However when WP Alchemy Meta Boxes store the values into the domain, they aren't saved with delimiters nor spaces, so it's much like: onetwothreefourfive...

Here's what I have so far:

<?php $meta = get_post_meta(get_the_ID(), $custom_metabox->get_the_id(), TRUE); ?>
<li>Via: <?php foreach ($meta['g2m_via'] as $link) { ?><a href="<?php echo $link['g2m_via-link']; ?>">
<?php
$prefix = ', ';
$words = array();
$words[] = $link['g2m_via-title'];
$words = array_map("unserialize", array_unique(array_map("serialize", $words)));
for($i = 0; $i < count($words); $i++){ $fruitlist = implode(', ', $words); print_r($fruitlist); } 
?></a><?php } ?></li>

$link['g2m_via-title'] is simply the name of the link that is stored in the meta field, i.e. Link1 would be the name, google,,com would be the link (which is not important here, I have that working). The other variables are all there. The $prefix variable does nothing, it was meant to act as a separator, like: $val .= $prefix . '' $link['g2m_via-title']; . ''; however, it causes: Link1, Link 1,Link 2, Link 1, Link 2, Link 3.

So far with that code, I've gotten the closest to what I want:

Link1Link2Link3

But it needs to be: Link1, Link2, Link3, and so on without the comma on the last link title.

Output of var_dump($link):

array(2) { 
    ["g2m_via-title"]=> string(7) "JoyStiq" 
    ["g2m_via-link"]=> string(22) "joystiq.com"; 
}JoyStiq 
array(2) { 
    ["g2m_via-title"]=> string(9) "GrindGadget" 
    ["g2m_via-link"]=> string(16) "grindgadget.com"; 
} GrindGadget 
array(2) { 
    ["g2m_via-title"]=> string(13) "Engadget" 
    ["g2m_via-link"]=> string(13) "engadget.com"; 
} Engadget

What I WANT it to look like so ["g2m_via-title"] will stop duplicating:

array[1] { 
    ["g2m_via-title"]=> "JoyStiq" 
    ["g2m_via-link"]=> "joystiq.com"; 
}
array[2] { 
    ["g2m_via-title"]=> "GrindGadget" 
    ["g2m_via-link"]=> "grindgadget.com"; 
}
array[3] { 
    ["g2m_via-title"]=> "Engadget" 
    ["g2m_via-link"]=> "engadget.com"; 
}

3 of the countless other pieces of code that I've tried: http://pastebin.com/wa0R8sDw.

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1条回答 默认 最新

  • douyuben9434
    douyuben9434 2011-08-27 15:06
    已采纳

    Assuming this data structure:

    $links = array(
        array( 
            "g2m_via-title" => "JoyStiq",
            "g2m_via-link"  => "joystiq.com"
        ),
        array( 
            "g2m_via-title" => "GrindGadget",
            "g2m_via-link"  => "grindgadget.com"
        ),
        array( 
            "g2m_via-title" => "Engadget",
            "g2m_via-link"  => "engadget.com"
        )
    );
    

    This'll do:

    $output = array();
    foreach ($links as $link) {
        $output[] = sprintf('<a href="http://%s">%s</a>',
                            $link['g2m_via-link'],
                            htmlentities($link['g2m_via-title']));
    }
    
    echo join(', ', $output);
    

    So will this in PHP 5.3+:

    echo join(', ', array_map(function ($link) {
        return sprintf('<a href="http://%s">%s</a>',
                       $link['g2m_via-link'],
                       htmlentities($link['g2m_via-title']));
    }, $links));
    
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