计算未显示正确天数的天数

Question

I need help.. Is this right?

Start Date: Mar 16, 2014

End Date: Mar 19, 2014

Results: 2 Days

$plantEnd = get_the_author_meta('plantEnd', $sellerID );
$plantStart = get_the_author_meta('plantStart', $sellerID );

$future = $plantEnd;

$d = new DateTime($future);
echo $d->diff(new DateTime())->format('%a').' Days';

Why does it says 2 days? Isn't it 3 days? Im confused..

Answer 1

Since you aren't actually using $plantStart in your code and instead using the current time, you're basically getting a difference between now (the time the script was run, on server's time zone) and the start of Mar 19, 2014 (0h:0m:0s). So what you are really getting is something like 2 days 5 hours 3 minutes 25 seconds (depending on when you run it vs. server time.

for example, when I run this locally:

$d->diff(new DateTime())->format('%d:%H:%i:%s');

I get 2:04:59:25

So there's more to it than just getting that "2" returned.. you're just not formatting for it.

And again, you aren't actually using the $plantStart anywhere either. So if you were to do this:

<?php
$plantEnd = '2014-03-19';//get_the_author_meta('plantEnd', $sellerID );
$plantStart = '2014-03-16'; //get_the_author_meta('plantStart', $sellerID );

$future = $plantEnd;

$d = new DateTime($future);
echo $d->diff(new DateTime($plantStart))->format('%d:%H:%i:%s');
?>

You will see it outputs 3:00:0:0 (or you could continue to just use %d and get the "3"). This is because $plantStart (presumably - based on your post) just specifies yyyy-mm-dd, so passing just the yyyy-mm-dd value will put the hh:mm:ss at 0:0:0 (beginning of day) , so it will be a full day's calculation, which has the effect of "rounding up" to the whole day increment.