doudou1309 2011-04-12 16:26
浏览 48
已采纳

too long

I'm not sure this is possible, but the code I tried using first is:

mysql_query ("CREATE TABLE My_table as ( SELECT * FROM CPE LEFT JOIN Greenwich_j20 ON CPE.cust_index = Greenwich_j20.cust_index LEFT JOIN Liverpool_j20 ON CPE.cust_index = Liverpool_j20.cust_index)")
 or die ("this certainly didn't work
");

The query itself works fine, and the syntax for the table works fine, but the combination is what it really doesn't like. Does it have a problem creating a table from a left join query?

  • 写回答

1条回答 默认 最新

  • duanna5749 2011-04-12 16:30
    关注

    If there is any auto increment column in your existing tables that will be not remain auto_increment in the table to be created.

    You could try by selecting columns instead of * there should be an error of column Ambiguous.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 在获取boss直聘的聊天的时候只能获取到前40条聊天数据
  • ¥20 关于URL获取的参数,无法执行二选一查询
  • ¥15 液位控制,当液位超过高限时常开触点59闭合,直到液位低于低限时,断开
  • ¥15 marlin编译错误,如何解决?
  • ¥15 有偿四位数,节约算法和扫描算法
  • ¥15 VUE项目怎么运行,系统打不开
  • ¥50 pointpillars等目标检测算法怎么融合注意力机制
  • ¥20 Vs code Mac系统 PHP Debug调试环境配置
  • ¥60 大一项目课,微信小程序
  • ¥15 求视频摘要youtube和ovp数据集