如何评估条件中的所有表达式？

Question

I know PHP uses lazy-evaluation / short-circuit operators. But say I wanted to evaluate all the expressions in a condition, for example:

$a = "Apple";
$b = "Banana";
$c = "Cherry";

function check($fruit) {
    if ($fruit != "Banana") {
        echo "$fruit is good.
";
        return true;
    } else {
        echo "$fruit is bad.
";
        return false;
    }
}

if (check($a) && check($b) && check($c)) {
    echo "Yummy!
";
}

Because of lazy-evaluation, this will only output:

Apple is good.
Banana is bad.

Rather than the desired output of:

Apple is good.
Banana is bad.
Cherry is good.

This is useful in form validation for instance.

So my question: Is there any way to force all expressions in a condition to be evaluated in PHP, and if not, what would be the best/quickest way to get the desired result in the example above?

Answer 1

You can use bitwise AND (single ampersand: &)

$a = "Apple";
$b = "Banana";
$c = "Cherry";

function check($fruit) {
    echo ($fruit != "Banana") ? "$fruit is good.
" : "$fruit is bad.
";
}

if (check($a) & check($b) & check($c)) {
    echo "Yummy!
";
}

Prints:

Apple is good.

Banana is bad.

Cherry is good.

Example: http://sandbox.onlinephpfunctions.com/code/07092a9d6636ae8ddafce024d7cc74643e311e9c