C＃正则表达式匹配（相当于php_match_all）

Question

Here is working php code

<?php
$str = '<users>
<user id="1" value1="afaaf" value2="racad" value3="xarcd">User1</user>
<user id="2" value1="fsvgvdsg" value2="wdafsc" value3="aefvbdfg">User2</user>
<user id="3" value1="chthb" value2="rtvfascf" value3="xasedfvg">User3</user>
</users>';
$out = '';
if(preg_match_all('|<user id="(.*)" value1="(.*)" value2="(.*)" value3="(.*)">(.*)</user>|',$str,$matches))
{
    for($i=0;$i<count($matches[1]);$i++)
    $out .= $matches[1][$i].'|'.$matches[2][$i].'|'.$matches[3][$i].'|'.$matches[4][$i].'|'.$matches[5][$i]."
";

    echo $out;
}
 ?>

This is what I get

1|afaaf|racad|xarcd|User1
2|fsvgvdsg|wdafsc|aefvbdfg|User2
3|chthb|rtvfascf|xasedfvg|User3

C# code

    string patt = "<user id=\"(.*)\" value1=\"(.*)\" value2=\"(.*)\" value3=\"(.*)\">(.*)</user>";
    string str = "<users><user id=\"1\" value1=\"afaaf\" value2=\"racad\" value3=\"xarcd\">User1</user><user id=\"2\" value1=\"fsvgvdsg\" value2=\"wdafsc\" value3=\"aefvbdfg\">User2</user><user id=\"3\" value1=\"chthb\" value2=\"rtvfascf\" value3=\"xasedfvg\">User3</user></users>";
    MatchCollection mc;
    Regex r = new Regex(patt);
    mc = r.Matches(str);

    for (int i = 0; i < mc.Count; i++)
        textBox1.Text += mc[i].Value + "
";

and I get

<user id=\"1\" value1=\"afaaf\" value2=\"racad\" value3=\"xarcd\">User1</user><user id=\"2\" value1=\"fsvgvdsg\" value2=\"wdafsc\" value3=\"aefvbdfg\">User2</user><user id=\"3\" value1=\"chthb\" value2=\"rtvfascf\" value3=\"xasedfvg\">User3</user>

You can see that string what i get from c# code isn't even close to my php result.

How to get result like from my php code?

Hope you understand what is my problem here.

Thanks

Answer 1

try this :

change (.*) to (.*?) in you RegEx pattern

and modify your snippet as:

for (int i = 0; i < mc.Count; i++)
    textBox1.Text += mc[i].Groups[1].Value + mc[i].Groups[2].Value + mc[i].Groups[3].Value + + mc[i].Groups[4].Value + mc[i].Groups[5].Value + "
";