dongquanlin1885 2012-08-12 19:25
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JS - 检查长度函数

I've got code:

function check($ile,$co,$gdzie)
{
  if (document.forms.form.$co.value.length >= $ile){
    document.forms.form.$gdzie.focus();
  }
}

And it isn't working. Error (in Google Chrome checked):

Uncaught TypeError: Cannot read property 'value' of undefined script.js:39
check script.js:39
onkeyup

And it's my html code:

<p><label><?php echo TEL; ?>: <input type='text' name='tel' size='9' maxlength='9' onkeypress="keyPressNumb(event);" onKeyUp="check(9,'tel','pesel');"></label></p>
<label><?php echo PESEL; ?>:<span class='red'>*</span> <input type='text' name='pesel' size='11' maxlength="11" onKeyUp="check11();" onkeypress="keyPressNumb(event);"></label></p>
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1条回答 默认 最新

  • dongshi1606 2012-08-12 19:47
    关注

    Try document.forms.form[$co].value.length, as you can not use a variable when accessing a value of an object via dot notation.

    In your code, js expects a property $co in the object document.forms.form. When you want to access a property via a variable, you have to use brackets to access the property.

    document.bar = "hello world";
    
    var foo = "bar";
    document.foo // undefined, because document has no property "foo"
    document[foo] // "hello world"
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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