duanli3277 2011-05-09 19:32
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sql数据导出脚本,创建损坏的文件

Ok, so I have the following script that will export data from my database using php. Everything works fine, except when I try to open the file in excel, I get "file is corrupt". I have used this script before, and I cannot figure out why it's not working. It may be a simple solution that I cannot see. Thanks in advance!

$link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error());
mysql_select_db($db) or die("Can not connect.");

$result = mysql_query("SHOW COLUMNS FROM trans",$link);
$i = 0;
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_assoc($result)) {
$csv_output .= $row['Field'].",";
$i++;
  }
}
$csv_output .= "
";

$values = mysql_query("SELECT * FROM trans",$link);
while ($rowr = mysql_fetch_row($values)) {
for ($j=0;$j<$i;$j++) {
$csv_output .= $rowr[$j].",";
  }
$csv_output .= "
";
}

$filename = date("Y-m-d_H-i",time());
header("Content-type: application/vnd.ms-excel");
header("Content-disposition: csv" . date("Y-m-d") . ".csv");
header( "Content-disposition: filename=".$filename.".csv");
print $csv_output;

exit;
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2条回答 默认 最新

  • douyun7285 2011-05-09 19:37
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    I think the Content-type is incorrect. Try using this instead:

    header("Content-type: text/csv");
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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