dongtui6347 2015-07-24 18:14
浏览 405

.getJSON.done()函数不调用else .fail()总是被调用

I have written html page which takes an input from user and on click submit calls a javascript function. The html page is given below:

<body>
        <input type="text" id="input_"/>
        <input type="button" id="submit" value="Get tweets"/>
        <div id="results"></div>
</body> 

and the javascript is:

$("#submit").click(function() {
        $.getJSON("tweets.php?q="+$('#input_').val())
        .done(function(data) {
            console.log(data);
        })
    });

the url in .getJSON is actually localhost/tweets.php?q=(userInput) but the url doesnt return anything in getJSON.done function however if i use .fail(err) and display err on console it prints the returned data on console. Also if I manually open for example: localhost/tweets.php?q=mkx on browse the data is displayed on browser. I cant seem to find any problem in the code. The tweets.php file is below:

$url = 'https://api.twitter.com/1.1/search/tweets.json';
                $getfield = '?q=%23'.$_GET["q"];
                $requestMethod = 'GET';
                $twitter = new TwitterAPIExchange($settings);
                echo $twitter->setGetfield($getfield)
                             ->buildOauth($url, $requestMethod)
                             ->performRequest(true);  

Any help would be appriciated.

  • 写回答

0条回答 默认 最新

    报告相同问题?

    悬赏问题

    • ¥15 ETLCloud 处理json多层级问题
    • ¥15 matlab中使用gurobi时报错
    • ¥15 这个主板怎么能扩出一两个sata口
    • ¥15 不是,这到底错哪儿了😭
    • ¥15 2020长安杯与连接网探
    • ¥15 关于#matlab#的问题:在模糊控制器中选出线路信息,在simulink中根据线路信息生成速度时间目标曲线(初速度为20m/s,15秒后减为0的速度时间图像)我想问线路信息是什么
    • ¥15 banner广告展示设置多少时间不怎么会消耗用户价值
    • ¥15 可见光定位matlab仿真
    • ¥15 arduino 四自由度机械臂
    • ¥15 wordpress 产品图片 GIF 没法显示