尝试在PHP中交替行颜色

Question

I'm looking to alternate row colors using PHP function. Here's what I have (although it does not work):

function row($year) {
    if($year%2) 
        $color == "#FFF";
    else
        $color == "#000";
}

for ($year=2013; $year<=2023; $year++) 
    {
    row($year);
    echo "<tr bgcolor='$color'><td>$year</td><td>$tdate</td></tr>";
    }

Basically, if a year is odd I would like the color of the row to be white. If even, black.

Answer 1

From W3c

15.1.1 Background color - bgcolor attribute has been deprecated in favor of style sheets for specifying background color information.

now what should you do is

function row($year) {
    return ($year % 2 == 0) ? "#FFFFFF" : "#000000";
}

for ($year = 2013; $year <= 2023; $year++) {
    echo "<tr style='background-color:".row($year).";'><td>$year</td><td>$tdate</td></tr>";
}

however its looks like you are not aware of what == does its a equal to operator its not assignment operator

what assignment operator do is assign right hand side value to left hand for example

what Comparison Operators(==) do is

$a == $b    Equal   TRUE if $a is equal to $b after type juggling.

second you also there is the scope of a variable

The scope of a variable is the context within which it is defined. For the most part all PHP variables only have a single scope. This single scope spans included and required files as well.

above is quoted from php manual to read more check this