交替颜色HTML表PHP

Question

I am trying to get my table to alternate colors but I am having some difficulty.

 if ($i % 2 == 0)
    $color = "grey";
    else
    $color = "white"; $i++;
    $table .= "<tr style=backround-color=$color>"; 

This does not work. I have tried this as well but it did not work either.

$table .= "<tr:nth-child(even) {background: #CCC};  tr:nth-child(odd) {background: #FFF}; >"; 

Answer 1

You misspelled background and you don't use = in CSS, you use :. I also added quotes around your attribute values as it is best practice:

$table .= "<tr style='background-color:$color'>";

The last line in your question isn't even close to valid HTML or CSS. Looks kinda neat though.