尝试在另一个try catch块中捕获块

Question

I have the following scenario:

In my .db.inc.php file I'm connecting to a database:

try {
    $dbh = new PDO('mysql:host=' . HOST . ';dbname=' . DATABASE , USER_DB, PASSWORD_DB);
}
catch (PDOException $e) {
    die('Error!: ' . $e->getMessage() . '<br/>');
}

Then I run some functions before I need the connection, but I know that the connection is established as I don't have an error thrown.

Now I need to update my database:

include('.db.inc.php');
try {

/...
$sql = "UPDATE de_request_products SET report_id = :report_id WHERE request_id = :request_id";
$stmt = $dbh->prepare($sql);
$stmt->bindValue(':report_id', $report_number, PDO::PARAM_STR);
$stmt->bindValue(':request_id', $report_request_number, PDO::PARAM_STR);
$stmt->execute();
}
catch (PDOException $e){
die('Error!: ' . $e->getMessage() . '<br/>');
}

If above written try block fails, I want to have a try catch block in the Exception Handler to update the database:

// ....
catch (PDOException $e){
  try {

   //SEND EMAIL AND

     $sql = "INSERT INTO de_failed_requests (datum, reason) VALUES (:datum, :reason)";
     $stmt = $dbh->prepare($sql);
     $stmt->bindValue(':datum', $date, PDO::PARAM_STR);
     $stmt->bindValue(':reason', $e->getMessage(), PDO::PARAM_STR);
     $stmt->execute();
   } catch (PDOException $f) {
     die('NOTHING WORKS AT ALL!'. $f->getMessage());
     }
     die('Error!: ' . $e->getMessage() . '<br/>');
 }

Would this be the way to go or is there a more efficient way?