index.php没有显示。 而是显示错误页面

Question

i have a page with 4 links namely 1st.php, 2nd.php, 3rd.php, and 4th.php. my index.php displays the 3rd.php as default. i also created a 404.php (error page) so that when a user edits the URL it will not redirect to the index.php, instead it will display the error page. the problem is when i open my index.php page, it displays the error page instead. need help. this is my code:

 <?php 

  $quarters = array('Q1', 'Q2', 'Q3', 'Q4');
        $quarter = 'Q3';

        if(isset($_GET['quarter']) && in_array($_GET['quarter'], $quarters)) {
          $quarter = $_GET['quarter'];  
        }

        switch($quarter) {
          case 'Q1' :
            $quarter = 'firstq2012.php';
          break;
          case 'Q2' :
            $quarter = 'secondq2012.php';
          break;
          case 'Q3' :
            $quarter = 'thirdq2012.php';
          break;
          case 'Q4' :
            $quarter = 'fourthq2012.php';
          break;
        }

    $pages = array('Q1','Q2','Q3','Q4');
    if (in_array($_GET['quarter'], $pages)){            
                    include_once $quarter;  
 }
 else {
 header('Location: 404.php');
  }
?>

Answer 1

Your code can be cleaned up a lot.

Try using this intead:

<?php 
$quarters = array('Q1' => 'firstq2012.php', 'Q2' => 'secondq2012.php', 'Q3' => 'thirdq2012.php', 'Q4' => 'fourthq2012.php');
if(isset($_GET['quarter'])) {
    if(in_array($_GET['quarter'], array_keys($quarters))) {
        include_once $quarters[$_GET['quarter']];
    } else {
        header('Location: 404.php');
    }
} else {
    include_once $quarters['Q3'];
}
?>