douhuan1979 2008-12-10 14:13 采纳率: 100%
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用PHP布[重复]

Dup of Some Basic PHP Questions

Hello,

I have a heap of tinyint fields in a mysql database I need to show with PHP. At the moment I am doing something like this:

if ($row['PAYPAL_ACCEPT'] == "1"){

$paypal = "Yes";

else

$paypal = "No";

}

For each field, which is tedious and seems like there should be a better way, than using an if clause for each field. If there is, what is it?

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  • doucheng9058 2008-12-10 14:32
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    Building on what's already been suggested:

    // $columns = string array of column names
    // $columns = array('PAYPAL_ACCEPT' ... );
    foreach($columns as $column) {
      $$column = $row[$column] ? 'YES' : 'NO';
    }
    

    then you can access variables using the column names as variable names:

    print $PAYPAL_ACCEPT;
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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