从PHP函数返回值

Question

what is wrong with the following code? Hope you understand what I'm trying to do. I'm not very familiar with functions.

function test ($variable) {
   $one = 3;
   if ($variable == 10) {
       $one = "2";
   }
   return $one;
}

foreach ($array as $arraypart) { 
   $part = explode(',',$arraypart);
   test($part[0]);
   echo $one;
}

Answer 1

You need to assign the result of function to a variable:

$one = test($part[0]);