Json_decode抛出“试图获取非对象的属性”

Question

I'm trying to use the simple weather API, but somehow it doesn't recognize it as an object whatever I do. This is my code:

$url = "https://www.amdoren.com/api/weather.php?api_key=za8LEJ8F9mcHK8SvLxdM98rM9mNFjW&lat=40.7127837&lon=-74.0059413";
$curl = curl_init($url);
$curl_response = curl_exec($curl);
$jsonobj = json_decode($curl_response);
$msg = "Temperature in ".$city."will be: ". $jsonobj->forecast->max_c;

and this is the data I'm trying to reach with $jsonojb->forecast->max_c:

{
 "error" : 0,
 "error_message" : "-",
 "forecast":[ 
 {"date":"2016-12-02",
 "avg_c":8,
 "min_c":5,
 "max_c":11,
 "avg_f":46,
 "min_f":41,
 "max_f":52,
  (...)

but it doesn't work. What am I doing wrong guys?

Answer 1

forecast is an array, so you have to use like this:

$forecast = $jsonobj->forecast;
$forecast[0]->max_c;