PHP正则表达式和URL解析

Question

How can I utilize preg_replace in PHP to parse a url.

Say I have the url

http://google.com?id=123

and I want to access each part of the url such that

echo $protocol;

would print

http

or

echo $domain;

would print

google

and

echo $upperDomain;

prints

com

and finally,

echo $rest;

would print

?id=123

Answer 1

there is a function for that: parse_url()

$url = 'http://google.com?id=123';    
print_r(parse_url($url));

prints:

Array
(
    [scheme] => http
    [host] => google.com
    [query] => id=123
)