doucheng7808 2011-07-28 16:19
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用JS和PHP做任何“后端媒体查询”的方法?

The project I am working on consists of a grid showing content. I would like to resize each item on the grid to a fourth of the viewport's size. This would be very easy with Javascript, but there is some backend stuff that needs to be aware of the size of each item:

I am using Timthumb to resize the image of item to its appropiate size, so I would need to detect the viewport's width, and send the appropiate value (the viewport's width / 4) to the php that serves each item, so it tells Timthumb the appropiate size to use.

What would be the best approach to this problem?

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  • dongxue7306 2011-07-28 16:31
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    How about when requesting the page, in $(document).ready, detect the size of viewport using jQuery and pass it in an AJAX request?

    $(document).ready(function () {
        var height = $(window).height();
        var width = $(window).width();
        $.ajax({
            type: 'POST',
            url: image.php,
            data: {
                "height": height,
                "width": width
            },
            success: function (data) {
                $("#viewarea").html(data);
            },
        });
    });
    

    at PHP side you can just get it and return the data

    $_POST['height']
    $_POST['width']
    
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