Php mysql结果进入无限循环

Question

Hi i have sql query result stored in the database.I have to check if any row contains string 'N;' then the next sql statement should execute.I have many such strings thats why want to execute my next sql statement.I have tried following code but when i try to run the code it goes to infinite loop.Thank you. Here is my php code:

while ($row = mysql_fetch_assoc($result)) {
        $config= $row['configuration'];     
        if($config=='N;')
        {
            $sql="SELECT DISTINCT ad_news_texte.id, ad_news_texte.headline, ad_news.datum_archiv FROM autodo.ad_news_texte INNER JOIN autodo.ad_news_oe ON ad_news_texte.news_id = ad_news_oe.id_ad_news INNER JOIN autodo.ad_news ON ad_news_oe.id_ad_news = ad_news.id WHERE ad_news.datum_archiv BETWEEN curdate( ) - INTERVAL DAYOFWEEK( curdate( ) ) +28 DAY AND curdate( )";
            $result = mysql_query($query, $myConnection);
        }
        else{                               
            $html .= '<table id="news">                     
                <a href="news.php?id=">
                <p class="welcome-subheadline"> '. $config .'</p></a>                   
                </table>';
        }
    }

Answer 1

Ok, so I miss some information, but I will try to solve your problem either way:

In the case if your sql fetch is identical to your sql statement in the loop, than you code should look like this: ( In this case I do not see the reason for the if statement )

$sql="SELECT DISTINCT ad_news_texte.id, ad_news_texte.headline, ad_news.datum_archiv FROM autodo.ad_news_texte INNER JOIN autodo.ad_news_oe ON ad_news_texte.news_id = ad_news_oe.id_ad_news INNER JOIN autodo.ad_news ON ad_news_oe.id_ad_news = ad_news.id WHERE ad_news.datum_archiv BETWEEN curdate( ) - INTERVAL DAYOFWEEK( curdate( ) ) +28 DAY AND curdate( )";
$result = mysql_query($sql, $myConnection);

while ($row = mysql_fetch_assoc($result)) {
        $config= $row['configuration'];     
        if($config=='N;')
        {
            // If the sql is the same no need for another fetch
        }
        else{                               
            $html .= '<table id="news">                     
                <a href="news.php?id=">
                <p class="welcome-subheadline"> '. $config .'</p></a>                   
                </table>';
        }
    }

In the second case, when the sql statements are differ, than your code should look like this:

$result = mysql_query($sql, $myConnection);
while ($row = mysql_fetch_assoc($result)) {
        $config= $row['configuration'];     
        if($config=='N;')
        {
           $sql2="SELECT DISTINCT ad_news_texte.id, ad_news_texte.headline, ad_news.datum_archiv FROM autodo.ad_news_texte INNER JOIN autodo.ad_news_oe ON ad_news_texte.news_id = ad_news_oe.id_ad_news INNER JOIN autodo.ad_news ON ad_news_oe.id_ad_news = ad_news.id WHERE ad_news.datum_archiv BETWEEN curdate( ) - INTERVAL DAYOFWEEK( curdate( ) ) +28 DAY AND curdate( )";
           $result2 = mysql_query($sql2, $myConnection);
           while ($row2 = mysql_fetch_assoc($result2)) {
               //The rest of the code
           }

         }
            else{                               
                $html .= '<table id="news">                     
                    <a href="news.php?id=">
                    <p class="welcome-subheadline"> '. $config .'</p></a>                   
                    </table>';
            }
        }