duaevb1511 2014-01-06 06:29
浏览 32

PHP根据条件创建数组或字符串

In the following code, I'm trying to create an array or a string based on if type is true or false. If type were true, then i need to create an array else I need to keep things as a string. I was trying as below, but it does not seem to work. Can you help?

<?php
$type = True;

if($type){
    $body = "body['body']"; //Start an array
} else {
    $body = 'body'; //Just a string
}

$body  = 'Hello'; //$body = the value from up there

print_r($body);
?>

Expected Results:

If type = true //Array
print_r($body);
Array ([body] => Hello)

If type = false //String
print_r($body); 
Hello

Edit The content for the array or string is outside the if and comes after it. I need to start as a array or sting based on the type.

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4条回答 默认 最新

  • dongzhao1930 2014-01-06 06:31
    关注
    $type  = true;
    $value = 'Hello';
    
    if($type){
        $body['body'] = $value;
    } else {
        $body = $value;
    }
    
    print_r($body);
    
    评论

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