使用函数在if else语句中不起作用PHP [重复]

Question

This question already has an answer here:

• Using namespace in if / else statements 4 answers

I'm trying to use the browscap-php in a if else statement in Apache & PHP 5+. I'm using the Browscap.php file like this below as a example.

Working example:

<?php 
   require 'Browscap.php';
   use phpbrowscap\Browscap;

   if ($newdata == "1") { 
       $current_browser = $bc->getBrowser();
   } else {

   }

?>

Not working example:

<?php 

   if ($newdata == "1") { 
       require 'Browscap.php';
       use phpbrowscap\Browscap;
       $current_browser = $bc->getBrowser();
   } else {
   // do not load anything dealing with browscap
   }
?>

The working example works fine but the second I place the use function in the if else statement it doesn't work. I don't want browscap loaded when I don't need to check for that information. How would I go about doing this?

</div>

Answer 1

Quoting from the manual:

The use keyword must be declared in the outermost scope of a file (the global scope) or inside namespace declarations. This is because the importing is done at compile time and not runtime, so it cannot be block scoped.

(my emphasis)