<?php
class X {
function foo() {
echo "Class Name:".get_class($this)."<br>"; //it displays Y... :)
echo get_class($this)::$public_var; //not working
echo Y::$public_var; //works
Y::y_method(); //works
get_class($this)::y_method(); //not working
$classname = get_class($this);
$classname::y_method(); // again not working.. :(
}
function bar() {
$this->foo();
}
}
class Y extends X {
public static $public_var = "Variable of Y Class";
public function y_method()
{
echo "Y class method";
}
}
$y = new Y();
$y->bar();
?>
my only question is how to get access members of y class only with dynamically providing class name without changing current structure.
如何在PHP中使用带有范围解析运算符的get_class()?
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1条回答 默认 最新
- duandong9195 2011-07-18 09:34关注
You are looking for
get_called_class()
class X { function foo() { $that = get_called_class(); echo $that::$private_var; echo $that::y_method(); } function bar() { $this->foo(); } } class Y extends X { public static $private_var = "Variable of Y Class"; public function y_method() { echo "Y class method"; } } $y = new Y(); $y->bar();
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