PHP正则表达式匹配字母数字字符串与一些（但不是全部）标点符号

Question

I've written a regular expression in PHP to allow strings that are alpha-numeric with any punctuation except & or @. Essentially, I need to allow anything on a standard American keyboard with the exception of those two characters. It took me a while to come up with the following regex, which seems to be doing what I need:

if (ereg("[^]A-Za-z0-9\[!\"#$%'()*+,./:;<=>?^_`{|}~\-]", $test_string)) {
  // error message goes here
}

Which brings me to my question... is there a better, simpler, or more efficient way?

Answer 1

Have a look at character ranges:

@[!-%'-?A-~]+@

This will exclude the characters & (\0x26) and @ (0x40). Looking at an ASCII Table,you can see how this works: The exclamation mark is the first character in the ASCII set, that is not whitespace. It will then match everything up to and including the % character, which immediately precedes the ampersand. Then the next range until the @ character, which lies between ? and A. After that, we match everything unto the end of the standard ASCII character set which is a ~.

Update

To make things more readable, you might also consider to do this in two steps: At first, filter anything outside of the default ASCII range.

@[!-~]+@

In a second step, filter your undesired characters, or simply do a str_pos on the characters.

At the end, you can compare it with what you started to see whether it contained any undesired characters.

Instead, you could also use a regex such as this for the second step. /[^@&]+/

The steps are interchangeable and doing a str_pos on @ or & as a first step, to identify bad characters, may be better performance wise.