通过组合变量的名称输出变量

Question

I have the following in a for loop over $x. $x is from 1 to 100. I have variables t1 to t100 already assigned. I want to echo them without typing each one individually, hence the for loop, but the following does not work:

echo "<br>'$t.$x'";

How could I fix this?

Answer 1

You would have to combine the variable names:

echo ${"t".$x};

but this reeks of imperfect design. Why not use an array instead?