找到数组-PHP的分数正数和负数

Question

I have an array.Its have positive, negative and zero value.Now i want to count those number of positive, negative and zero value then divided each group by number of array count.I have tried below way:

<?php

$arr = ['-4','3','-9','0','4','1'];
$countNum = count($arr);
//print_r($countNum);
foreach ($arr as $key => $value) {
    if ($value<0) {
        continue;
    }elseif($value==0){
        continue;
    }else{
        $result = $value/$countNum;
        echo $result."</br>";
    }
}
?>

Output is :

0.5
0.66666666666667
0.16666666666667

But i want and should be:

for positive, 3/6=0.500000
for negative, 2/6=0.333333
for zero, 1/6=0.166667

Answer 1

Try this code.

<?php
$zero = '0';
$positive = '0';
$negative = '0';
$arr = array('-4','3','-9','0','4','1');
$total = count($arr);
foreach ($arr as $num){
    if ($num > '0'){
    $positive++;
    } else if ($num < '0'){
    $negative++;
    } else {
        $zero++;
    }
}
echo "Positive: ".$positive/$total;
echo '<br />';
echo "Negative: ".$negative/$total;
echo '<br />';
echo "Zero: ".$zero/$total;
?>